Class 12

Math

Calculus

Differential Equations

The solution of the differential equation $dxdy =x_{2}−2x_{3}y_{3}3x_{2}y_{4}+2xy $ is

Connecting you to a tutor in 60 seconds.

Get answers to your doubts.

The curve satisfying the equation $dxdy =x(y_{3}−x)y(x+y_{3}) $ and passing through the point $(4,−2)$ is

A curve is such that the mid-point of the portion of the tangent intercepted between the point where the tangent is drawn and the point where the tangent meets the y-axis lies on the line $y=x˙$ If the curve passes through $(1,0),$ then the curve is

Find the orthogonal trajectory of $y_{2}=4ax$ (a being the parameter).

The degree of the differential equationdydx−x=(y−xdydx)−4 is

What is the solution of satisfying?

The normal to a curve at $P(x,y)$ meet the x-axis at $G˙$ If the distance of $G$ from the origin is twice the abscissa of $P$ , then the curve is a (a) parabola (b) circle (c) hyperbola (d) ellipse

Solve $ydx−xdy+gxdx=0$

The degree and order respectively of the differential equation are dydx=1x+y+1.